Before viewing this page, it would be helpful to learn Distributive Law.

A **Linear Equation** is an algebraic equation composed of a **constant** (e.g. x = 3) or a **variable to the power of 1** (e.g. 2a + 3 = 13).

Remember that 2a means 2 × a.

**Solving an equation** is to figure out what number is represented by the variable. For example, in the equation 2a + 3 = 13, the variable a is 5.

Some hints to solve are:

**Do the opposite operation to what is shown in the equation.****Move variables (letters) to the left side of the equation.****Move constants (numbers on their own) to the right side of the equation.****If you change the side, you change the sign.**

Solve this linear equation with the **variable on one side**.

x + 3 = 10

x = 10 – 3

x = 7

Solve this linear equation with the **variable on one side**.

4x + 3 = 11

4x = 11 – 3

4x = 8

x = | 8 |

4 |

x = 2

Solve this linear equation with the **variable on one side**.

3a – 5 = 7

3a = 7 + 5

3a = 12

a = | 12 |

3 |

a = 4

**Q1.** 5x + 6 = 16
**Q2.** 9x – 2 = 25
**Q3.** –3x = –21
**Q4.** 3x – 5 = –1
**Q5.** –2x + 8 = 16

**Answers**
**A1.** 2
**A2.** 3
**A3.** 7
**A4.** –2
**A5.** –4

Solve this linear equation with the **variable in brackets on one side**.

2 ( x + 3 ) = 16

2x + 6 = 16

2x = 16 – 6

2x = 10

x = | 10 |

2 |

x = 5

Solve this linear equation with the **variable in brackets on one side**.

4 ( x – 2 ) = 20

4x – 8 = 20

4x = 20 + 8

4x = 28

x = | 28 |

4 |

x = 7

**Q1.** 5 ( x + 2 ) = 25
**Q2.** 6 ( x + 4 ) = 42
**Q3.** 9 ( x + 5 ) = 54
**Q4.** 5 ( x – 2 ) = 5
**Q5.** –2 ( x + 8 ) = –4

**Answers**
**A1.** 3
**A2.** 3
**A3.** 1
**A4.** 3
**A5.** 10

Solve this linear equation with the **variable on both sides**.

*Remember: Move variables (letters) to the left side of the equation. Move constants (numbers on their own) to the right side of the equation.
If you change the side, you change the sign.*

4x + 8 = 2x + 14

4x – 2x = 14 – 8

2x = 6

x = 3

Solve this linear equation with the **variable on both sides**.

5x – 3 = 3x + 11

5x – 3x = 11 + 3

2x = 14

x = 7

**Q1.** 7x – 6 = 3x + 10
**Q2.** 9x + 5 = 3x + 23
**Q3.** 10x + 4 = 5x – 6
**Q4.** x + 2 = 2x + 5
**Q5.** 5x = 2x – 9

**Answers**
**A1.** 4
**A2.** 3
**A3.** –2
**A4.** –3
**A5.** –3

Solve this linear equation with **fractions**.

*Multiply both fractions by a number that will cancel out the fractions' denominator. In this example, we will multiply both fractions by 10.*

x | = | ( x + 3 ) |

2 | 5 |

5x = 2 ( x + 3 )

5x = 2x + 6

5x - 2x = 6

3x = 6

x = 2

x | = | ( x – 4 ) |

3 | 6 |

**Answer**

–4